Answer
$\dfrac{1}{12}$
Work Step by Step
Here, $a=\dfrac{1}{16}, r=\dfrac{1}{4}$
The sum of a geometric series can be found as:
$S=\dfrac{a}{1-r}=\dfrac{\dfrac{1}{16}}{1-\dfrac{1}{4}}=\dfrac{\dfrac{1}{16}}{\dfrac{3}{4}}=\dfrac{1}{12}$
University Calculus: Early Transcendentals (3rd Edition)
by Hass, Joel R.; Weir, Maurice D.; Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0321999584
ISBN 13:
978-0-32199-958-0
Chapter 9 - Section 9.2 - Infinite Series - Exercises - Page 497: 8
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
