## University Calculus: Early Transcendentals (3rd Edition)

We have: $\lim\limits_{n \to \infty} \dfrac{n}{n^2+3}$ We can see that the degree of the denominator is more than the numerator, so: $\lim\limits_{n \to \infty} \dfrac{n}{n^2+3}=0$ Hence, the test is inconclusive.