University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 9 - Section 9.2 - Infinite Series - Exercises - Page 497: 30

Answer

The test is inconclusive.

Work Step by Step

We have: $\lim\limits_{n \to \infty} \dfrac{n}{n^2+3}$ We can see that the degree of the denominator is more than the numerator, so: $\lim\limits_{n \to \infty} \dfrac{n}{n^2+3}=0$ Hence, the test is inconclusive.
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