## University Calculus: Early Transcendentals (3rd Edition)

$\dfrac{1}{7}$
The Nth partial sum of a geometric series can be found as: $s_n=\dfrac{a(1-r^n)}{1-r}$ The sum of a geometric series can be found as: $S=\dfrac{a}{1-r}$ The common ratio for a geometric series is $a=\dfrac{1}{8}, r=\dfrac{1}{8}$; Thus, $S=\dfrac{\dfrac{1}{8}}{1-\dfrac{1}{8}}=\dfrac{1}{7}$; converges