Answer
$\dfrac{1}{7}$
Work Step by Step
The Nth partial sum of a geometric series can be found as:
$s_n=\dfrac{a(1-r^n)}{1-r}$
The sum of a geometric series can be found as:
$S=\dfrac{a}{1-r}$
The common ratio for a geometric series is $a=\dfrac{1}{8}, r=\dfrac{1}{8}$;
Thus,
$S=\dfrac{\dfrac{1}{8}}{1-\dfrac{1}{8}}=\dfrac{1}{7}$; converges