## University Calculus: Early Transcendentals (3rd Edition)

The half-life for carbon is 5730 years. so, $k=\dfrac{\ln 2}{5730}$ $C=C_0e^{-\dfrac{\ln 2}{5730}t}$ Now, at $t=5000$ $C=C_0e^{-\dfrac{\ln 2}{5730}(5000)}$ so, $C \approx 0.5462 C_0$ This means that 54.62 % of carbon-14 remained in Otzi at the time of discovery in 1991.