Answer
$2 \sqrt y -\dfrac{x^3}{3} =C$
Work Step by Step
We have: $\dfrac{dy}{dx}=x^2 \sqrt y$
or, $\dfrac{dy}{\sqrt y}=x^2 dx$
We have to integrate the above expression:
$\int \dfrac{dy}{\sqrt y}= \int x^2 dx$
or, $2 (\int \dfrac{dy}{2\sqrt y})= \int x^2 dx$
This implies: $2 \sqrt y=\dfrac{x^3}{3}+C$
Hence, $2 \sqrt y -\dfrac{x^3}{3} =C$