Answer
$$y=\frac{\ln2}{\ln3-\ln2}$$
Work Step by Step
$$3^y=2^{y+1}$$
Take the natural logarithm of both sides:
$$\ln(3^y)=\ln(2^{y+1})$$
Remember that $\ln x^a=a\ln x$
$$y\ln3=(y+1)\ln2$$ $$y\ln3=y\ln2+\ln2$$ $$y(\ln3-\ln2)=\ln2$$ $$y=\frac{\ln2}{\ln3-\ln2}$$
