Answer
$$\int^{32}_1\frac{1}{5x}dx=\ln2$$
Work Step by Step
$$A=\int^{32}_1\frac{1}{5x}dx=\frac{1}{5}\int^{32}_1\frac{1}{x}dx$$ $$A=\frac{1}{5}\ln|x|\Big]^{32}_1$$ $$A=\frac{1}{5}(\ln32-\ln1)$$ $$A=\frac{1}{5}(\ln32-0)=\frac{\ln32}{5}$$ $$A=\frac{\ln(2^5)}{5}=\frac{5\ln2}{5}$$ $$A=\ln2$$
