University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 7 - Practice Exercises - Page 420: 10



Work Step by Step

$$A=\int^{32}_1\frac{1}{5x}dx=\frac{1}{5}\int^{32}_1\frac{1}{x}dx$$ $$A=\frac{1}{5}\ln|x|\Big]^{32}_1$$ $$A=\frac{1}{5}(\ln32-\ln1)$$ $$A=\frac{1}{5}(\ln32-0)=\frac{\ln32}{5}$$ $$A=\frac{\ln(2^5)}{5}=\frac{5\ln2}{5}$$ $$A=\ln2$$
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