Answer
$$\int e^x\sin(e^x)dx=-\cos(e^x)+C$$
Work Step by Step
$$A=\int e^x\sin(e^x)dx$$
Set $u=e^x$, which means $$du=e^xdx$$
Therefore, $$A=\int \sin udu$$ $$A=-\cos u+C$$ $$A=-\cos(e^x)+C$$
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