University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 6 - Section 6.5 - Work - Exercises - Page 381: 28

Answer

$110.60$ ft-lb

Work Step by Step

$W=\dfrac{1}{2}mv^2$ Here, we have $m=6.5~oz\implies m=\dfrac{6.5~oz}{(16~oz/lb)(32~m/s^2)} =\dfrac{6.5}{512}~slugs$ and $v=132~ft/s$ Plug in the values. $W=(\dfrac{1}{2})(\dfrac{6.5}{512})(132)^2\approx 110.60$ ft-lb
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