University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 6 - Section 6.5 - Work - Exercises - Page 381: 24

Answer

$50$ ft-lb

Work Step by Step

$W=\dfrac{1}{2}mv^2$ Here, we have $m=\dfrac{1}{8} lb=\dfrac{1}{256}~lb$ and $v=160 ft/s$ Plug in the values: $W=(\dfrac{1}{2})(\dfrac{1}{256})(160)^2=50$ ft-lb
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