University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 6 - Section 6.3 - Arc Length - Exercises - Page 370: 13



Work Step by Step

The formula to calculate the arc length is as follows: $L=\int_{c}^{d} \sqrt {1+[f'(x)]^2} dx$ Re-write the equation as follows: $L=\int_{-\pi/4}^{\pi/4} \sec^2 y dy $ Separate the terms and integrate as follows: $L=[ \tan y]_{-\pi/4}^{\pi/4} \\= (\tan \dfrac{\pi}{4} -\tan \dfrac{-\pi}{4} ) \\= 2$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.