University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 6 - Section 6.3 - Arc Length - Exercises - Page 370: 12

Answer

$\dfrac{373}{430}$

Work Step by Step

The formula to calculate the arc length is as follows: $L=\int_{c}^{d} \sqrt {1+[f'(x)]^2} dx$ Re-write the equation as follows: $L=\int_{1/2}^{1} [x^4+\dfrac{1}{4x^4}] dx $ Separate the terms and integrate as follows: $L=[ \dfrac{x^5}{5}+\dfrac{x^{-4+1}}{(-4+1)} ]_{1/2}^{1} \\=\dfrac{31}{60} +\dfrac{7}{12} \\=\dfrac{373}{430}$
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