University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 6 - Section 6.3 - Arc Length - Exercises - Page 370: 11

Answer

$\dfrac{53}{6}$

Work Step by Step

The formula to calculate the arc length is as follows: $L=\int_{c}^{d} \sqrt {1+[f'(x)]^2} dx$ Re-write the equation as follows: $L=\int_{1}^{3} [x^2+\dfrac{1}{4x^2}] dx $ Separate the terms and integrate as follows: $L=\int_{1}^{3} [x^2+\dfrac{1}{4x^2}] dx \\=[ \dfrac{x^3}{3}-\dfrac{1}{4x} ]_1^{3}=\dfrac{53}{6}$
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