University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 5 - Section 5.2 - Sigma Notation and Limits of Finite Sums - Exercises: 22

Answer

$\pi$

Work Step by Step

$\sum\limits_{k=1}^5\frac{\pi k}{15}=\frac{\pi }{15}\cdot\sum\limits_{k=1}^5k=\frac{\pi }{15}\cdot(1+2+3+4+5)=\frac{\pi }{15}\cdot15=\pi$
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