#### Answer

$\sum\limits_{k=1}^5(-1)^{k+1}\cdot\frac{1}{k}$

#### Work Step by Step

As we can see, the fraction's denominator is always growing by one, and the fraction's sign is always changing, therefore the formula is: $\sum\limits_{k=1}^5(-1)^{k+1}\cdot\frac{1}{k}$