Answer
$7$
Work Step by Step
$\sum\limits_{k=1}^2\frac{6k}{k+1}=\frac{6\cdot1}{1+1}+\frac{6\cdot2}{2+1}=\frac{6}{2}+\frac{12}{3}=3+4=7$
University Calculus: Early Transcendentals (3rd Edition)
by Hass, Joel R.; Weir, Maurice D.; Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0321999584
ISBN 13:
978-0-32199-958-0
Chapter 5 - Section 5.2 - Sigma Notation and Limits of Finite Sums - Exercises - Page 299: 1
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