University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 5 - Practice Exercises - Page 343: 51


$$\int e^x\sec^2(e^x-7)dx=\tan(e^x-7)+C$$

Work Step by Step

$$A=\int e^x\sec^2(e^x-7)dx$$ We set $a=e^x-7$, which means $$da=e^xdx$$ Therefore, $$A=\int \sec^2ada$$ $$A=\tan a+C$$ $$A=\tan(e^x-7)+C$$
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