University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 5 - Practice Exercises - Page 343: 86


$$\int^{3\pi/4}_{\pi/4}\csc^2x dx=2$$

Work Step by Step

$$A=\int^{3\pi/4}_{\pi/4}\csc^2x dx$$ $$A=-\cot x\Big]^{3\pi/4}_{\pi/4}$$ $$A=-\cot\frac{3\pi}{4}+\cot\frac{\pi}{4}$$ $$A=-(-1)+1$$ $$A=2$$
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