University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 5 - Practice Exercises - Page 343: 115


See definition below.

Work Step by Step

The fundamental theorem of calculus states that the average value of any function $f(x) $ on the interval $[m,n]$ is: $\dfrac{1}{n-m}\int_m^n f'(x) dx=\dfrac{1}{n-m}[f'(x)]_m^n$ or, $=\dfrac{f(n)-f(m)}{n-m}$ This represents an average change of $f(x)$ on $[m,n]$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.