Answer
a) Need to caculate the value of inverse trigonometric funtion $cos$.
$cos^{-1}(\frac{1}{2})=\frac{\pi}{3}$
b) Need to caculate the value of inverse trigonometric funtion $cos$.
$cos^{-1}(-\frac{1}{\sqrt 2})=(\frac{3\pi}{4})$
c) Need to caculate the value of inverse trigonometric funtion $cos$.
$cos^{-1}(\frac{\sqrt 3}{2})=\frac{\pi}{6}$
Work Step by Step
a) Need to caculate the value of inverse trigonometric funtion $cos$.
$cos^{-1}(\frac{1}{2})=\frac{\pi}{3}$
b) Need to caculate the value of inverse trigonometric funtion $cos$.
$cos^{-1}(-\frac{1}{\sqrt 2})=(\frac{3\pi}{4})$
c) Need to caculate the value of inverse trigonometric funtion $cos$.
$cos^{-1}(\frac{\sqrt 3}{2})=\frac{\pi}{6}$