Answer
a) Need to caculate the value of a trigonometric funtion $sin$.
$sin^{-1}(\frac{1}{2})=\frac{\pi}{6}$
b) Need to caculate the value of a trigonometric funtion $sin$.
$sin^{-1}(-\frac{1}{\sqrt 2})=-(\frac{\pi}{4})$
c) Need to caculate the value of a trigonometric funtion $sin$.
$sin^{-1}(\frac{\sqrt 3}{2})=\frac{ \pi}{3}$
Work Step by Step
a) Need to caculate the value of a trigonometric funtion $sin$.
$sin^{-1}(\frac{1}{2})=\frac{\pi}{6}$
b) Need to caculate the value of a trigonometric funtion $sin$.
$sin^{-1}(-\frac{1}{\sqrt 2})=-(\frac{\pi}{4})$
c) Need to caculate the value of a trigonometric funtion $sin$.
$sin^{-1}(\frac{\sqrt 3}{2})=\frac{ \pi}{3}$