Answer
a) Need to caculate the value of a trigonometric funtion $sin$.
$sin^{-1}(-\frac{1}{2})=-\frac{\pi}{6}$
b) Need to caculate the value of a trigonometric funtion $sin$.
$sin^{-1}(\frac{1}{\sqrt 2})=(\frac{\pi}{4})$
c) Need to caculate the value of a trigonometric funtion $sin$.
$sin^{-1}(\frac{-\sqrt 3}{2})=\frac{- \pi}{3}$
Work Step by Step
a) Need to caculate the value of a trigonometric funtion $sin$.
$sin^{-1}(-\frac{1}{2})=-\frac{\pi}{6}$
b) Need to caculate the value of a trigonometric funtion $sin$.
$sin^{-1}(\frac{1}{\sqrt 2})=(\frac{\pi}{4})$
c) Need to caculate the value of a trigonometric funtion $sin$.
$sin^{-1}(\frac{-\sqrt 3}{2})=\frac{- \pi}{3}$
