University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 3 - Section 3.6 - The Chain Rule - Exercises - Page 158: 3


$\frac{dy}{dx} = 3cos u=3cos(3x+1)$

Work Step by Step

$\frac{dy}{du} = \frac{d(sinu)}{dx} = cos u$ and $\frac{du}{dx} = \frac{d(3x+1)}{dx} = 3$ So, $\frac{dy}{dx} = \frac{dy}{du}*\frac{du}{dx}$ $\frac{dy}{dx} = 3cos u$
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