#### Answer

$\frac{dy}{dt} = -6$

#### Work Step by Step

Given that $\frac{dx}{dt} = 3$ and $y=x^2$
on differentiating y with respect to time
$\frac{d(y)}{dt}$ = $\frac{d x^2}{dt}$
$\frac{dy}{dt} = \frac{2xdx}{dt}$
so $\frac{dy}{dt} = 2x\times 3$
$\frac{dy}{dt} = 6x$
when x=-1
then $ \frac{dy}{dt} = 6\times (-1)$
Thus, the answer is $\frac{dy}{dt} = -6$