University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 3 - Section 3.10 - Related Rates - Exercises - Page 187: 3

Answer

$\frac{dy}{dt}$ =10

Work Step by Step

Given that $\frac{dx}{dt}$ = 2 and $y=5x$ on differentiating y with respect to time, we get: $\frac{dy}{dt}$ = $\frac{d 5x}{dt}$ $\frac{dy}{dt}$ = $5\frac{d x}{dt}$ so $\frac{dy}{dt}$ = 5 $\times$ 2=10 Thus the answer is: $\frac{dy}{dt}$ =10
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