University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 3 - Section 3.10 - Related Rates - Exercises - Page 187: 13

Answer

a) ${\frac{dV}{dt}}={\pi r^2 \frac{dh}{dt}}$ b) ${\frac{dV}{dt}}={2\pi r h \frac{dr}{dt}}$ c) ${\frac{dV}{dt}}={\pi r^2 \frac{dh}{dt}}+{2\pi r h \frac{dr}{dt}}$

Work Step by Step

The volume of a cylinder is (V) =${\pi r^2 h}$ a) We differentiate both sides, keeping r constant: ${\frac{dV}{dt}}={\pi r^2 \frac{dh}{dt}}$ b) We differentiate both sides, keepking h constant: ${\frac{dV}{dt}}={2\pi r h \frac{dr}{dt}}$ c) We differentiate both sides, treating both r and h as variables: ${\frac{dV}{dt}}={\pi r^2 \frac{dh}{dt}}+{2\pi r h \frac{dr}{dt}}$
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