University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 3 - Practice Exercises - Page 204: 140



Work Step by Step

Given $s=20$ $\frac{dV}{dt}=1200$ $V=s^3$ on differentiating above, we get: $\frac{dV}{dt}=3s^2\frac{ds}{dt}$ $\frac{dV}{dt}=3\times20^2\frac{ds}{dt}$ $\frac{ds}{dt}=\frac{1200}{1200}=1$ thus, $\frac{ds}{dt}=1\frac{cm}{min}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.