Answer
$-16$
Work Step by Step
As we know that $div F=\dfrac{\partial A}{\partial x}i+\dfrac{\partial B}{\partial y}j+\dfrac{\partial C}{\partial z}k$
Now, we have
$div F=-1-1=-2$
This implies that
$div F=\iiint_R (-2) dA=(-2)[(2)(2)(2)]=-16$
University Calculus: Early Transcendentals (3rd Edition)
by Hass, Joel R.; Weir, Maurice D.; Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0321999584
ISBN 13:
978-0-32199-958-0
Chapter 15 - Section 15.8 - The Divergence Theorem and a Unified Theory - Exercises - Page 906: 5
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