Answer
$112+6\pi$
Work Step by Step
As we know that $div F=\dfrac{\partial A}{\partial x}i+\dfrac{\partial B}{\partial y}j+\dfrac{\partial C}{\partial z}k$
Now, we have
$Flux =\iiint_{o} 12x+12y+2 dz dy dx$
Also,
$Flux =\nabla \cdot F=\int_{0}^{3}\int_{0}^{\pi/2}\int_{0}^{2} (12r \cos \theta+2r \sin \theta +2) dr d\theta dz$
This implies that
$\int_{0}^{3}(32+2\pi+\dfrac{16}{3}) dz = 112+6\pi$
