University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 14 - Section 14.3 - Area by Double Integration - Exercises - Page 772: 6

Answer

$1$

Work Step by Step

Our aim is to integrate the integral as follows: $ Area =\iint_D dA $ $\int^{e}_{1} \int^{2 \ln (x) }_{ln x} dy dx =\int^{e}_{1} \ln (x) dx $ or, $=[x \ln (x)-x]^e_1$ or, $=(e \ln e -e)-(1 \ln 1-1)$ or, $=1$
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