Answer
$1$
Work Step by Step
Our aim is to integrate the integral as follows:
$ Area =\iint_D dA $
$\int^{e}_{1} \int^{2 \ln (x) }_{ln x} dy dx =\int^{e}_{1} \ln (x) dx $
or, $=[x \ln (x)-x]^e_1$
or, $=(e \ln e -e)-(1 \ln 1-1)$
or, $=1$