Answer
$2$
Work Step by Step
Our aim is to integrate the integral as follows:
$ Area =\iint_D dA $
or, $=\int^{2}_{0} \int^{2-x}_{0} dy \space dx $
or, $= \int^{2}_{0}(2-x) \space \space dx $
or, $=[2x-\dfrac{x^2}{2}]^2_0$
or, $=(2)(2)-\dfrac{2^2}{2}$
or, $=2$
