University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 14 - Section 14.3 - Area by Double Integration - Exercises - Page 772: 5

Answer

$1$

Work Step by Step

Our aim is to integrate the integral as follows: $ Area =\iint_D dA $ $\int^{ln2}_{0} \int^{e^x}_{0} \space dy \space dx =\int^{ln (2)}_{0} [e^x]\space dx $ or, $=[e^x]^{\ln2}_0$ or, $=e^{\ln 2}-e^{0}$ or, $=1$
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