University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 11 - Section 11.4 - The Cross Product - Exercises - Page 622: 14

Answer

${\bf( j+2k)}\times{\bf (i)}=2{\bf j} -{\bf k}$ .

Work Step by Step

${\bf( j+2k)}\times{\bf (i)}=\left|\begin{array}{lll} {\bf i} & {\bf j} & {\bf k}\\ 0 & 1 & 2\\ 1 & 0 & 0 \end{array}\right|$ $=(0)-(0-2){\bf j}+(0-1){\bf k}$ $=2{\bf j} -{\bf k}$
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