University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 11 - Section 11.4 - The Cross Product - Exercises - Page 622: 11

Answer

${\bf( i-k)}\times{\bf (j+k)}={\bf i-j} +{\bf k}$

Work Step by Step

${\bf( i-k)}\times{\bf (j+k)}=\left|\begin{array}{lll} {\bf i} & {\bf j} & {\bf k}\\ 1 & 0 & -1\\ 0 & 1 & 1 \end{array}\right|$ $=(0+1){\bf i}-(1-0){\bf j}+(1-0){\bf k}$ $={\bf i-j} +{\bf k}$
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