University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 11 - Section 11.4 - The Cross Product - Exercises - Page 622: 10

Answer

$({\bf i-k})\times{\bf j}={\bf i}+{\bf k}$ .

Work Step by Step

$({\bf i-k})\times{\bf j}=\left|\begin{array}{rrr} {\bf i} & {\bf j} & {\bf k}\\ 1 & 0 & -1\\ 0 & 1 & 0 \end{array}\right|$ $=(0+1){\bf i}-0+(1-0){\bf k}$ $={\bf i}+{\bf k}$
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