## University Calculus: Early Transcendentals (3rd Edition)

$2x+7y+2z=-10$
Here, the normal equation of a plane is: $n=\lt 2,7,2 \gt$ We know that the standard equation of a plane passing through the point $(x_0,y_0,z_0)$ is written as: $a(x-x_0)+b(y-y_0)+c(z-z_0)=0$ Then, for the point $(-2,0,-3)$, we have $2(x+2)+7(y-0)+2(z+3)=0$ or, $2x+4+7y+2z+6=0$ or, $2x+7y+2z=-10$