University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 11 - Practice Exercises - Page 639: 56


$59.5^{ \circ}$

Work Step by Step

The formula to calculate the angle between the vector v and the x-axis is: $ \theta = \cos ^{-1} (\dfrac{v_x}{|v|})$ Here, $v=\lt 3,-5,1 \gt$ $|v|=\sqrt{3^2+(-5)^2+(1)^2}= \sqrt {35}$ Thus, $ \theta = \cos ^{-1} (\dfrac{v_x}{|v|})=\cos ^{-1} (\dfrac{3}{ \sqrt {35}})$ or, $ \theta =59.5^{ \circ}$
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