Answer
$\lt 0,-3,3 \gt$
Work Step by Step
Since, we have
$n=\lt 2,1,-1 \gt $ and $v=\lt 1,1,1 \gt$
Thus, the cross product is: $n \times v=i(-1+1)-j(2+1)+k(2+1)=-3j+3k$
Hence, we have $\lt 0,-3,3 \gt$
University Calculus: Early Transcendentals (3rd Edition)
by Hass, Joel R.; Weir, Maurice D.; Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0321999584
ISBN 13:
978-0-32199-958-0
Chapter 11 - Practice Exercises - Page 639: 51
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