University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 10 - Section 10.1 - Parametrizations of Plane Curves - Exercises - Page 562: 4

Answer

$y=2-\displaystyle \frac{2}{3}x.\qquad 0\leq x\leq 3$

Work Step by Step

Express t in terms of one variable and substitute it into the other equation. $x=3-3t$, $3t=3-x$ $t=\displaystyle \frac{3-x}{3},\qquad\left[\begin{array}{l} 0\leq\frac{3-x}{3}\leq 1\\ 0\leq 3-x\leq 3\\ -3\leq-x\leq 0\\ 3\geq x\geq 0 \end{array}\right]$ Substitute $t$ into the other equation. $y=2(\displaystyle \frac{3-x}{3}),\qquad 0\leq x\leq 3$ $y=2-\displaystyle \frac{2}{3}x,\qquad 0\leq x\leq 3$ To graph, create a function value table using values for t, in ascending order of t, calculating the x- and y-coordinates of points on the graph. Plot and join the points obtained with a smooth curve, noting the direction in which t increases.
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