University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 10 - Section 10.1 - Parametrizations of Plane Curves - Exercises - Page 562: 8

Answer

$\displaystyle \frac{y^{2}}{25}+\frac{x^{2}}{16}=1$

Work Step by Step

Square both parametric equations: $\left\{\begin{array}{ll} x^{2}=16\cos^{2}t & /\div 16\\ y^{2}=25\sin^{2}t & /\div 25 \end{array}\right.\qquad \Rightarrow\left\{\begin{array}{l} \frac{x^{2}}{16}=\cos^{2}t \\ \frac{y^{2}}{25} = \sin^{2}t \end{array}\right.$ Add the two equations$,\qquad\cos^{2}t +\sin^{2}t=1$ $\displaystyle \frac{y^{2}}{25}+\frac{x^{2}}{16}=1$ (an ellipse centered at the origin, with the main axis on the y-axis). To graph, create a function value table using values for t, in ascending order of t, calculating the x- and y-coordinates of points on the graph. Plot and join the points obtained with a smooth curve, noting the direction in which t increases.
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