University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 10 - Practice Exercises - Page 593: 27



Work Step by Step

Here, we have $r=\dfrac{-3}{2}\csc \theta$ This implies that $r \sin \theta =\dfrac{-3}{2}$ Thus, we have $y=\dfrac{-3}{2}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.