Chapter 10 - Practice Exercises - Page 593: 24

$ y=x+1$

Here, we have $r \cos (\theta-\dfrac{3\pi}{4})=\dfrac{ \sqrt 2}{2}$ This implies that $r[\cos \theta \cos \dfrac{3\pi}{4}+\sin \theta \sin \dfrac{3\pi}{4}]=\dfrac{ \sqrt 2}{2}$ or, $-x+y=1$ Thus, we have $ y=x+1$