University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 10 - Practice Exercises - Page 593: 25

Answer

$x=2$

Work Step by Step

Here, we have $r =2\sec \theta$ This implies that $r=\dfrac{2}{\cos \theta}$ or, $r \cos \theta =2$ Thus, we have $x=2$
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