University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 1 - Section 1.1 - Functions and Their Graphs - Exercises - Page 13: 62



Work Step by Step

We can write the given statement as a relation: $V\:\propto\:\frac{1}{P}$ Let's introduce a proportionality constant $\:k\:$ to turn the relation into an equation as: $V=k\cdot \frac{1}{P}=\frac{k}{P}$ We can find the value of $\:k\:$ when we are given $\:P=14.7\:$ and $\:V=1000.$ $1000=\frac{k}{14.7}$ $\Rightarrow\: k=14700$ So, now our general equation $\:V=\frac{k}{P}\:$ becomes: $V=\frac{14700}{P}$ When $\:P=23.4,\:$ we have: $V=\frac{14700}{23.4}$ $\Rightarrow\: V=628.2$
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