University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 1 - Section 1.1 - Functions and Their Graphs - Exercises - Page 13: 61



Work Step by Step

We can write the given statement as a relation: $s\:\propto\:\frac{1}{r}$ Let's introdue a proportionality constant $\:k\:$ to turn the relation into an equation as: $s=k\cdot \frac{1}{r}$ We can find the value of $\:k\:$ when we are given $\:r=6\:$ and $\:s=4.$ $4=k\cdot \frac{1}{6}$ $\Rightarrow\: k=24$ So, now our general equation $\:s=k\cdot \frac{1}{r}\:$ becomes: $s=\frac{24}{r}$ When $\:v=10,\:$ we have: $s=\frac{24}{10}$ $\Rightarrow\: s=2.4$
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