University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 1 - Section 1.1 - Functions and Their Graphs - Exercises - Page 13: 60



Work Step by Step

We can write the given statement as a relation: $K\:\propto\:v^2$ Let's introdue a proportionality constant $\:a\:$ to turn the relation into an equation as: $K=a\cdot v^2$ We can find the value of $\:a\:$ when we are given $\:K=12,960\:$ and $\:v=18.$ $12960=a\cdot 18^2$ $\Rightarrow\: a=\frac{12960}{18^2}=\frac{12960}{324}$ $\Rightarrow\: a=40$ So, now our general equation $\:K=a\cdot v^2\:$ becomes: $K=40v^2$ When $\:v=10,\:$ we have: $K=40(10)^2$ $\Rightarrow\: K=4000$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.