Answer
$\ln5$
Work Step by Step
$$16\int_{0}^{1}\frac{x}{8x^{2}+2}dx=8\int_{0}^{1}\frac{d(x^{2})}{8x^{2}+2}$$
$$=\int_{0}^{1}\frac{d(8x^{2}+2)}{8x^{2}+2}$$
$$=\left | \ln(8x^{2}+2) \right |_{0}^{1}$$
$$=\ln10-\ln2$$
$$=\ln5$$
Thomas' Calculus 13th Edition
by Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0-32187-896-5
ISBN 13:
978-0-32187-896-0
Chapter 8: Techniques of Integration - Section 8.1 - Using Basic Integration Formulas - Exercises 8.1 - Page 448: 1
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