## Thomas' Calculus 13th Edition

$5 \cosh(\dfrac{ x}{5})+C$
As we are given that $\int \sinh (\dfrac{x}{5}) dx$ Since, $\int \sinh x dx=\cosh x +C$ Therefore, $\int \sinh (\dfrac{x}{5}) dx=\dfrac{ \cosh(\dfrac{ x}{5})}{\dfrac{1}{5}}+C$ or, $= 5 \cosh(\dfrac{ x}{5})+C$