Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 7: Transcendental Functions - Section 7.7 - Hyperbolic Functions - Exercises 7.7 - Page 430: 17

Answer

$\coth z$

Work Step by Step

As we know, $\dfrac{d}{dx} (\sinh x)=cosh x$ Given: $y=\ln (\sinh z)$ Now, $\dfrac{dy}{dz}= (\cosh z) \dfrac{1}{(\sinh z)} =\coth z$
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