Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 7: Transcendental Functions - Section 7.6 - Inverse Trigonometric Functions - Exercises 7.6 - Page 420: 9


$\frac{\sqrt 2}{2}$

Work Step by Step

$\sin(\cos^{-1}(\frac{\sqrt 2}{2}))= \sin(\frac{\pi}{4})=\frac{\sqrt 2}{2}$
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